#include<stdio.h>//三角形 int main() { printf("* "); printf("** "); printf("*** "); printf("**** "); printf("***** "); printf("****** "); printf("******* "); printf("******** "); printf("********* "); printf("********** "); }
#include<stdio.h> int main() { printf("********** "); printf("********** "); printf("********** "); printf("********** "); printf("********** "); printf("********** "); printf("********** "); printf("********** "); printf("********** "); printf("********** "); }
#include<stdio.h> int main()//十行倒三角型形 { printf("* * * * * * * * * * "); printf(" * * * * * * * * * "); printf(" * * * * * * * * "); printf(" * * * * * * * "); printf(" * * * * * * "); printf(" * * * * * "); printf(" * * * * "); printf(" * * * "); printf(" * * "); printf(" * "); return 0; }
#include<stdio.h> int main()//五级制成绩(A~E),输出相应的百分制成绩(0~100)区间 { char score; scanf("%c",&score); switch (score) { case 'A': printf("90~100"); break; case 'B': printf("80~89"); break; case 'C': printf("70~79"); break; case 'D': printf("60~69"); break; case 'E': printf("0~59"); break; } return 0; }
#include<stdio.h> int main()//计算华氏温度100°F对应的摄氏温度 { int F=100; int C; printf("C=%d",C=5*(F-32)/9); return 0; }
#include<stdio.h> int main()//100米自由落体 { int g=10; int t=3; int height; height=0.5*g*t*t; printf("height=%d",height); return 0; }
#include<stdio.h> int main()//输出整数的个位数字、十位数字和百位数字的值 { int a; scanf("%d",&a); while(a!=0) { printf("%d ",a%10); a=a/10; } return 0; }
#include<stdio.h> #include<math.h> int main()//分段函数 { double x; double y; scanf("%lf",&x); if(x>=0) y=sqrt(x); else y=pow(x+1,2)+2*x+1/x; printf("f(x)=%f",y); return 0; }
#include<stdio.h> #include<math.h> int main()//计算存款利息 { int money,year; double rate,interest; printf("输入存款金额: "); scanf("%d",&money); printf("输入存期: "); scanf("%d",&year); printf("输入年利率: "); scanf("%lf",&rate); interest=money*pow(1+rate,year)-money; printf("interest=%.2f ",interest); return 0; }
#include<stdio.h> int main()//阶梯电价 { float n; printf("月用电量: "); scanf("%f",&n); if(n<=50) printf("月电费:%f ",n*0.53); else printf("月电费:%f ",50*0.53+(n-50)*(0.53+0.05)); return 0; }